By now we have an idea about continuity and differentiability of various functions. We now move onto see the derivatives of differentiable functions by using product & quotient rule. For computing, the derivative of the composite functions, methods like chain rule, logarithmic differentiation are used. Then we learn about implicit differentiation for the functions defined as f(x,y) and in the last section higher order differentiation is seen.
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Question 1: In this question, a recursive form of a function is given and we use the chain rule to evaluate the derivative of the function. 06:39
Question 2: In this question, we are given a parametric form of function. We use the chain rule to calculate derivatives of x and y w.r.t the parameter t and then use parametric differentiation to arrive at first and second order derivatives required. 11:19
Question 3: In this question, we are given two functions, a condition on f(x) and a relation between g(x) in terms of first f(x) function and are asked to evaluate the derivative of g(x) at x=1. We will use the first principle of differentiation on the condition given for f(x) and arrive at the derivative of f(x) which is used in arriving at the result. 19:00
Question 4: In this question, we are given a composite function involving trigonometric, inverse trigonometric and exponential functions. The first step in the attempt to solve is to simplify the function. Then we will apply the quotient rule to arrive at the result. 23:42
Question 5: In this question, we look at the function given in the form of the determinant and begin to perform differentiation of determinant row by row to realize that each determinant is zero by properties of determinants. 29:43
Question 6: In this question, we look at the function given with infinite terms. In the first step to solving, we replace the infinite terms with y as it also represents the same function y = f(x) as given in the question. We then use mathematical manipulation to arrive at the result. 33:45
Question 7: In this video, we look into one of the basic Methods of Differentiation question in a form of implicit differentiation. We also encounter a combination of product rule, then chain rule and then again product rule. 36:28
Check out our other Videos on Mathematics!
Parabola - https://youtu.be/80jqjtaALfE
Relations and Functions - https://youtu.be/FLPoaWzIZuY
Complex Numbers - https://youtu.be/Go9K3jZ3yT8
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#Differentiation #Calculus #LogarithmicDifferentiation #ChainRuleCalculus #IITJEE #JEE #JEEPreparation #TargetJEE #JEEAdvanced #JEEMain #JEEMaths #JEEMainDifferentiation #JEEMainCalculus #JEEAdvancedCalculus
iit jee exam pattern Methods of Differentiation | JEE Calculus | Target JEE | Solved Questions | JEE Maths | |
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